Webb26 feb. 2024 · 10.2 Adding up the two equivalent fractions. Add the two equivalent fractions which now have a common denominator. Combine the numerators together, … WebbFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

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Webb13 juni 2024 · So, the simplified form is . Hence, First option is correct. Advertisement Advertisement Bradleybreonna21 Bradleybreonna21 Answer: a. b^3/8a^18. Step-by-step … Webb7a- (5b- (4c-3 (a+3b-2c))) Final result : 2 • (2a - 7b + 5c) Step by step solution : Step 1 :Equation at the end of step 1 : 7a - (5b - (4c - 3 • (a + 3b - 2c))) Step 2 : Step 3 :Pulling out … critical care journal abbreviation

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Webb30 mars 2024 · Transcript. Ex 12.2, 3 (Method 1) Subtract: (vii) 5a2 – 7ab + 5b2 from 3ab – 2a2 – 2b2 (3ab – 2a2 – 2b2) − (5a2 – 7ab + 5b2 ) = 3ab – 2a2 – 2b2 − 5a2 + 7ab − 5b2 = −2a2 − 5a2 − 2b2 − 5b2 + 3ab + 7ab = a2 (−2 − 5) + b2 (−2 − 5) + ab (3 + 7) = a2 (−7) + b2 (−7) + ab (10) = −7a2 − 7b2 + 10ab Ex 12.2, 3 (Method 2) Subtract: (vii) 5a2 – 7ab + 5b2 … Webb7×7 = 49 Then we know that 7 is a square root of 49. That is, if 72 = 49 then 7 = √ 49 Now suppose we found that a p× a = a That is, when we multiplied ap by itself we got the result a. This means that ap must be a square root of a. However, look at this another way: noting that a = a1, and also that, from the first rule, WebbFree solutions for NCERT Solutions - Mathematics, Class 7 Chapter 13 - Algebraic Expressions Exercise 12.2 question ... 7ab + 5b2) = 3ab – 2a2 – 2b2 – 5a2 + 7ab – 5b2 = 3ab + 7ab – 2a2 – 5a2 – 2b2 – 5b2 = 10ab – 7a2 – 7b2. Related Questions. Q2) Add:i) ii) iii) iv) v) vi) vii ... Simplify combining like terms:i) ii) iii) iv ... critical care letter of recommendation